Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops The Refactor Challenge Solution

Thomas Goepfert
seal-mask
.a{fill-rule:evenodd;}techdegree
Thomas Goepfert
Front End Web Development Techdegree Student 6,124 Points
Posted by Thomas Goepfert
.a{fill-rule:evenodd;}techdegree
Thomas Goepfert
Front End Web Development Techdegree Student 6,124 Points

Why won't this work?! Trying to combine the three Math objects into a single function. https://w.trhou.se/ds5mvibg4k

https://w.trhou.se/ds5mvibg4k

2 Answers

Emmanuel C
Emmanuel C
10,636 Points
Emmanuel C
Emmanuel C
10,636 Points

Using rgb for background color requires 3 numbers passed in as the red, green, and blue values. However you are only passing in 1 number. So one way to do it using the function you created would be something like...

var html = "";
function rgb () { 
  return Math.floor(Math.random() * 256);
}

for ( var i = 1; i <=10; i += 1 ) {
  var rgbColor = "rgb(" + rgb() + "," + rgb() +","+ rgb()+")";  
  html += '<div style = "background-color:' + rgbColor + ';"></div>';
}
document.write(html);

This way each red,green, and blue value is generated by your rgb function. I would suggest naming your function something different as rgb() is already used by css, and may seem a bit confusing as they are doing different things.