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JavaScript JavaScript Array Iteration Methods Array Manipulation Practice map()

3 Answers

Travis Alstrand
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Travis Alstrand
Data Analysis Techdegree Graduate 45,998 Points

Hey Joseph Quintiliano

This is happening because when using substring, the second number we provide is excluded. So using (0, 2) would only return index 0 & 1. Using (0, 3) would return index 0, 1 & 2.

You can read more on it here

Also, check your order of your => you'll want it to be >=.

Steven Parker
Steven Parker
229,783 Points

According to the MDN page for substring(), it returns the part of the string from the start index up to and excluding the end index. Another way to think about is arg2 - arg1 = how many.

So, with the values of 0 and 3, you get the characters at indexes 0, 1, and 2, but not 3. That's 3 letters.

With the values of 0 and 2, you only get back 0 and 1 (just 2 letters).


Update: I think Travis might have misunderstood part of the instructions. Your use of => is correct for creating an arrow function to pass to the map() method. The >= operator would be for a comparison expression.