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Python

Posted by ilhan KAYIHAN
ilhan KAYIHAN
6,664 Points

word guess game loop problem, always get a _ _ _ _

while True:
  s=['a','p','p','l','e']
  t1= input("Guess a word please:(quit: q) ")   

  if t1 == 'q':
    break
  elif t1 in s:
    x = 0
    k = 1
    for t1 in s[len(s)-(len(s)+x)]:
      print("_ "*(len(s)-(len(s)+x)) , s[len(s)-(len(s)+x)] , " _ "*(len(s)-k))  
      x +=1
      k +=1

2 Answers

Nathan Smutz
Nathan Smutz
9,492 Points
Nathan Smutz
Nathan Smutz
9,492 Points

My guess is that you want to show the letters that match "apple". So if someone enters "art", you would display "a _ _ _ _". Is that right?

In that case, you'd want a for loop which iterates across s and t1, checking whether the nth letter of s is the same as the nth letter of t1. The thing you want to watch out for is if t1 is shorter than s. So, if t1 is "art", the last letter is at t1[2]. If you try to check what's in t1[3], you'll get an error.

So, you need something like:

response = ""
for i in range(len(s)):
    if i < len(t1) and s[i] == t1[i]:
        response += s[i]
    else:
        response += "_"

print(response)
ilhan KAYIHAN
ilhan KAYIHAN
6,664 Points

Firstly we input a letter. In my loop, if t1 in s it gives always s [0] _ _ _ _. else lose. But I want Thé loop that outputs Thé true letter for Thé correct place. I couldn't Manage to make a loop in apple example; When you input a or p or l it always output: a _ _ _ _.

Nathan Smutz
Nathan Smutz
9,492 Points
Nathan Smutz
Nathan Smutz
9,492 Points

Since your input statement asks for a whole word, I think your solution is going to look something like my example above.

You're wondering why your original code is doing what it's doing. Just to simplify what you've got: len(s) - (len(s) + x) = len(s) - len(s) + x = 0 + x = x So lets simplify that where we see it:

while True:
  s=['a','p','p','l','e']
  t1= input("Guess a word please:(quit: q) ")   

  if t1 == 'q':
    break
  elif t1 in s:
    x = 0
    k = 1
    for t1 in s[x]:
      print("_ "*(x) , s[x] , " _ "*(len(s)-k))  
      x +=1
      k +=1

Lets look at that last piece: Particularly the lines: 

for t1 in s[x]:
      print("_ "*(x) , s[x] , " _ "*(len(s)-k))

Since x = 0 at this point, s[x] = s[0] = 'a'

So that works the same as:

for t1 in 'a':

Here, python is treats 'a' kind of like a list with one item in it. So, the for loop will only run once. So your output comes from running this one time.

   print("_ "*(x) , s[x] , " _ "*(len(s)-k))

As we saw earlier, x = 0 and k= 1. So the above line is equivalent to this:

   print("_ "*(0) , s[0] , " _ "*(len(s)-1))

Lets interpret len(s) = 5 too:

   print("_ "*(0) , s[0] , " _ "*(5-1))

And we know s[0] = 'a':

   print("_ "*(0) , 'a' , " _ "*(4))

Now, "_"*0 is just an empty string '' And, "_"*4 = '____'

So the line means:

   print('', 'a', '____')

Which prints out:

   a____