Jared Barr
1,911 Pointsword_count Bummer: Try again!
Hello, The error I am receiving is not very detailed, which hopefully means that I am close to the answer. This code seems to work in my workspace while not in the challenge:
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
#split sentence into list of words
#count how many words in list of words
def word_count(sentence):
word_list = sentence.lower().split()
count_list = []
for x in word_list:
count_list.append(word_list.count(x))
word_count_dict = dict(zip(word_list, count_list))
# for key,val in word_count_dict.items():
# print(key, ":", val)
1 Answer
Chris Freeman
Treehouse Moderator 59,509 PointsYou are SO close. The function needs to return a value. Return word_count_dict and you'll pass the challenge!
Jared Barr
1,911 PointsJared Barr
1,911 Points/)_-)
of course in the next exercise I have been utilizing return...
Thanks!