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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Word_count Challenge

This is the error I receive "Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!"

Here is my code:

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count (str):
    d = {}
    for word in str.lower().split(" "):
        if not word in d:
            d[word] = 1
        else:
            d[word] += 1
    return d

when I run:

print(word_count("I do not like it Sam I Am"))

I get

'do': 1, 'like': 1, 'sam': 1, 'i': 2, 'am': 1, 'it': 1, 'not': 1}

I'm missing something here...

1 Answer

Steven Parker
Steven Parker
230,230 Points

The challenges test your code with more complex data than shown in sample. The issue is hinted in the message "Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace", leave the argument to "split" empty. Providing a space causes it to split only on individual spaces.

Thanks! I was thinking in JavaScript where String.split() separates every character. Guess I should have read the docs more closely...

Steven Parker
Steven Parker
230,230 Points

Knowing other languages can pose extra challenges when learning a new one. :wink: