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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by William Ennals
William Ennals
9,441 Points

Word_count challenge: I checked my code in the work space and it works fine, but I get an error here.

Not sure how to fix this

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    words = string.split()
    word_dict = {}
    for word in words:
        if word.lower() in word_dict:
            count += 1
            word_dict.update({word.lower(): count})
        else:
            count = 1
            word_dict.update({word.lower(): count})
    return(word_dict)

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,967 Points

Try the given phrase twice with your code: 

word_count("I do not like it Sam I Am I do not like it Sam I Am")

count keeps incrementing with (wrong) result

{'i': 8, 'do': 3, 'not': 4, 'like': 5, 'it': 6, 'sam': 7, 'am': 9}
William Ennals
William Ennals
9,441 Points

Oh I just ran it and now I see the problem. Seems like there is an issue with the in statement so used in my for loop. I’ll have to play around with it to figure out how to change it

William Ennals
William Ennals
9,441 Points

For some reason, it’s counting the letters as well as words