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# word_count challenge task not working correctly: it works on workspace, but it didn't pass the checker

Adding the following to call the function:

```string = "I do not like it Sam I Am"
print(word_count(string))
```

I got:

```['i', 'do', 'not', 'like', 'it', 'sam', 'i', 'am']
{'i': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'sam': 1, 'am': 1}
```

Please tell me where I went wrong?

wordcount.py
```# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
word_list = (string.lower()).split()
print(word_list)
word_count = {}
for word in word_list:
count = 1
try:
if word_count[word] >= 1:
word_count[word] = count + 1
except KeyError:
word_count[word] = count
return word_count
```

Try testing with: "I like people, I like pets and I like ice cream". Notice that count is always 1 in every iteration. Also I recommend to change the name of your variable `word_count` since it is the same as your method. Hope it helps!

Thanks! count = 1 was not correct, how could I forget the age-old += 1 ?!!! ;)

```def word_count(string):
word_list = (string.lower()).split()
print(word_list)
word_count = {}
for word in word_list:
try:
if word_count[word] >= 1:
word_count[word] += 1
except KeyError:
word_count[word] = 1
return word_count

string = "I like people, I like pets and I like ice cream"
print(word_count(string))
```