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Python Python Collections (Retired) Dictionaries Managing Keys

Steven Wheeler
Steven Wheeler
2,330 Points
Posted by Steven Wheeler
Steven Wheeler
2,330 Points

word_count() Code Challenge, Python.. really stuck

So the challenge is: "Create a function named word_count() that takes a string. Return a dictionary with each word in the string as the key and the number of times it appears as the value."

I can't think how to increment the number of times it appears.. I know that currently the count will only go up to "2". I've been trying for about 45 minutes now and I just can't figure it out.. -_-.

I understand the flaw in my logic (count is either 1 or count += 1 (2)) but I have no idea how to make that counter only consider each individual instance of each word, rather than considering all instances of all words (if that makes sense!). 

def word_count(sentence):
  new_sentence = sentence.split(" ")
  newDict = {}
  for word in new_sentence:
    if word in newDict:
      count += 1

    newDict[word] = count
  return(newDict)

word_count("one two two three three three")

6 Answers

mrben
mrben
8,068 Points

You need to change what happens in your if statement as well as add an else.

If the word is not in the dictionary you can just set it to 1; otherwise increase it by 1.

Hint: Do away with the count variable.

Hope that helps!

Steven Wheeler
Steven Wheeler
2,330 Points
Steven Wheeler
Steven Wheeler
2,330 Points 
def word_count(sentence):
  new_sentence = sentence.split(" ")
  newDict = {}
  for word in new_sentence:
    if word in newDict:
      newDict[word] += 1
    else:
      newDict[word] = 1
  return(newDict)

word_count("one two two three three three")

Got it! Thank you! I finally did it -_-

mrben
mrben
8,068 Points

Congrats!

Ron Fisher
Ron Fisher
5,752 Points
Ron Fisher
Ron Fisher
5,752 Points

Stephen,

From the code posted above, I don't understand what "new_word" is doing. Do you mean:

for word in new_sentence:

Ron

Steven Wheeler
Steven Wheeler
2,330 Points
Steven Wheeler
Steven Wheeler
2,330 Points

Yes, apologies, I've updated it now. I tried to make the code a bit easier to read by naming the variables a bit more sensibly but I completely forgot to change that one!

Steve

MUZ140953 Herbert Samuriwo
MUZ140953 Herbert Samuriwo
7,929 Points
MUZ140953 Herbert Samuriwo
MUZ140953 Herbert Samuriwo
7,929 Points 
def word_count(sentence):
  new_sentence = sentence.split(" ")
  newDict = {}
  for word in new_sentence:
    if word in newDict:
      newDict[word] += 1
    else:
      newDict[word] = 1
  return(newDict)

this work for me,try this one

saro lin
PLUS
saro lin
Courses Plus Student 531 Points
saro lin
saro lin
Courses Plus Student 531 Points

The below code is really simple.

count=dict() a="I am that I am"

def word_count(a): words=a.split() for word in words: count[word]=count.get(word,0)+1 return count

saro lin
PLUS
saro lin
Courses Plus Student 531 Points
saro lin
saro lin
Courses Plus Student 531 Points

The below code is really simple.

count=dict() a="I am that I am"

def word_count(a): words=a.split() for word in words: count[word]=count.get(word,0)+1 return count

saro lin
PLUS
saro lin
Courses Plus Student 531 Points
saro lin
saro lin
Courses Plus Student 531 Points

The below code is really simple.

count=dict() a="I am that I am"

def word_count(a): words=a.split() for word in words: count[word]=count.get(word,0)+1 return count