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Start your free trialchunjie liu
Python Web Development Techdegree Student 1,815 Pointsword_count I have checked my code in the workspaces and i got the expected output But cannot check it
I still got Unexpected Output when i check it in the units: https://teamtreehouse.com/library/python-collections-2/dictionaries/word-count
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(item):
word_list=item.split(" ")
low_word_list=[]
for word in word_list:
low_word=word.lower()
low_word_list.append(low_word)
i=0
word_dict={}
while i<len(low_word_list):
j=1
if low_word_list[i] not in word_dict.keys():
word_dict.update({low_word_list[i]:j})
i+=1
else:
m=word_dict[low_word_list[i]]+1
word_dict.update({low_word_list[i]:m})
i+=1
return word_dict
1 Answer
Steven Parker
231,269 PointsYou're really close, and the "Bummer" message gave you a hint: "Be sure you're lowercasing the string and splitting on all whitespace!".
To split on "all whitespace" the argument to "split" should be left empty or set to None
.
chunjie liu
Python Web Development Techdegree Student 1,815 Pointschunjie liu
Python Web Development Techdegree Student 1,815 PointsOH! I got it! Thank you!!!
Steven Parker
231,269 PointsSteven Parker
231,269 Pointschunjie liu — Glad to help. You can mark a question solved by choosing a "best answer".
And happy coding!