Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Antoni Majewski
Antoni Majewski
3,128 Points

word_count - my solution isn't working and I don't understand why :(

Hello,

my code isn't working and I don't understand why - it's supposed to make a list out of string and late pop word out of list and count it to later wrap it up in dictionary - is my way of thinking bad? What's wrong?

Thanks

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string = list(string.lower())
    sting = string [:]
    word_amount = 1
    for word in sting:
        while word in sting:
            sting.pop(word)
            word_amount += 1
        dict = (**kwarg{"word": "word_amount"})

return(dict)

1 Answer

Steven Parker
Steven Parker
218,487 Points

Here's a few hints:

  • converting a string into a list breaks it up into single characters (not words)
  • you have not defined anything named "kwarg" (and it's not a function)
  • you'd want to build up the dictionary instead of replacing it each time
  • you can do this with just one loop (and no nesting)