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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Roy Law
Roy Law
2,537 Points
Posted by Roy Law
Roy Law
2,537 Points

[word_count] Not passing challenge even I can return correct result... Any help?

I test my code and I can return the correct answer in my terminal: {'i': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'sam': 1, 'am': 1}

Am I doing any mistake?? Please help and thanks a lot!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    word_array = string.lower().split(" ")
    result = {word: word_array.count(word) for word in word_array}
    return result
Alexander Davison
Alexander Davison
65,469 Points

Oh cool, I didn't know you could do "dictionary" comprehension :D

1 Answer

Steven Parker
Steven Parker
229,744 Points
Steven Parker
Steven Parker
229,744 Points

Try splitting on all whitespace.

You should have seen this error when you tried your code: "Bummer! Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!". The key hint there is "all whitespace". By giving a space argument to split, you restrict the split to just spaces. But with no argument, it will split on all whitespace.

Roy Law
Roy Law
2,537 Points
Roy Law
Roy Law
2,537 Points

Thanks a lot! Using split() instead of split(" ") fixed the problem!