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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Roy Law
Roy Law
2,537 Points

[word_count] Not passing challenge even I can return correct result... Any help?

I test my code and I can return the correct answer in my terminal: {'i': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'sam': 1, 'am': 1}

Am I doing any mistake?? Please help and thanks a lot!

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    word_array = string.lower().split(" ")
    result = {word: word_array.count(word) for word in word_array}
    return result

Oh cool, I didn't know you could do "dictionary" comprehension :D

1 Answer

Steven Parker
Steven Parker
229,608 Points

Try splitting on all whitespace.

You should have seen this error when you tried your code: "Bummer! Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!". The key hint there is "all whitespace". By giving a space argument to split, you restrict the split to just spaces. But with no argument, it will split on all whitespace.

Roy Law
Roy Law
2,537 Points

Thanks a lot! Using split() instead of split(" ") fixed the problem!