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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Kars Jansens
Kars Jansens
5,348 Points
Posted by Kars Jansens
Kars Jansens
5,348 Points

wordcount problem [python]

question: Alright, this one might be a bit challenging but you've been doing great so far, so I'm sure you can manage it.

I need you to make a function named word_count. It should accept a single argument which will be a string. The function needs to return a dictionary. The keys in the dictionary will be each of the words in the string, lowercased. The values will be how many times that particular word appears in the string.

Check the comments below for an example.

I have no idee how to fix this.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string.lower()
    for word in string:
        count = count + 1
        dit = {word:count}
    return dit

5 Answers

Timotheus Taruvinga
Timotheus Taruvinga
2,319 Points

Hie Kars I think you don't need no counting in a dictionary setup. you'll get your numbers in a haphazard way as they are in your >code. Check out for this pretty smart code. It does all you want.

def word_count(str):
    counts = dict()
    tim= str.lower()
    words = tim.split()
    for word in words:
        if word in counts:
            counts[word] += 1
        else:
            counts[word] = 1
    return counts
print( word_count('the quick brown Fox jumps over the lazy dog.'))
Kars Jansens
Kars Jansens
5,348 Points
Kars Jansens
Kars Jansens
5,348 Points

def word_count(sting): string = sting.lower() stringa = string.split() dit = {} for word in stringa: count = 1 for key in dit.keys(): if word == key: count = count + 1 dit.update({word:count}) else: dit.update({word:count}) return dit print(word_count("hoi ik ben kars"))

My output is '{}'.

Kars Jansens
Kars Jansens
5,348 Points
Kars Jansens
Kars Jansens
5,348 Points

the output is {}. once I head a dictionary returned with al the words but the count didn't work.

def word_count(string):
    strings = string.lower
    for word in string:
        if word is not in dic.keys():
            count = 1
            dic = {word: count}
        else:
            count = count + 1
            dic = {word: count}
Kars Jansens
Kars Jansens
5,348 Points
Kars Jansens
Kars Jansens
5,348 Points 
def word_count(sting):
    string = sting.lower()
    stringa = string.split()
    dit = {}
    count = 0
    for word in stringa:
        count = count + 1
        dit.update({word:count})
    return dit

print(word_count("hello ik ben ik kars"))

Can you just tell me how I need to do this? I really don't know.

Kars Jansens
Kars Jansens
5,348 Points
Kars Jansens
Kars Jansens
5,348 Points

You're right that is pretty smart code..