Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

wordcount.py - not sure what mistake I am coding in my code, please help

sample code:

def word_count(str_in): dict1 = {} lis = str_in.split(' ') for word in lis: if word.lower() in dict1: dict1[word.lower()] += 1 else: dict1.update({word.lower(): 1}) return dict1

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(str_in):
    dict1 = {}
    lis = str_in.split(' ')
    for word in lis:
        if word.lower() in dict1:
            dict1[word.lower()] += 1
        else:
            dict1.update({word.lower(): 1})
    return dict1

1 Answer

Hi there,

It is objecting to your split command. Omit the parameter and your code is fine:

lis = str_in.split()

Steve.