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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Pankaj Gupta
Pankaj Gupta
3,469 Points

wordcount.py - not sure what mistake I am coding in my code, please help

sample code:

def word_count(str_in): dict1 = {} lis = str_in.split(' ') for word in lis: if word.lower() in dict1: dict1[word.lower()] += 1 else: dict1.update({word.lower(): 1}) return dict1

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(str_in):
    dict1 = {}
    lis = str_in.split(' ')
    for word in lis:
        if word.lower() in dict1:
            dict1[word.lower()] += 1
        else:
            dict1.update({word.lower(): 1})
    return dict1

1 Answer

Steve Hunter
Steve Hunter
57,682 Points
Steve Hunter
Steve Hunter
57,682 Points

Hi there,

It is objecting to your split command. Omit the parameter and your code is fine:

lis = str_in.split()

Steve.