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# word_length.py

What is wrong with my code

```import re

def find_words(count, strang):
return re.findall(r'\w{'+ str(count) +'}', strang)
```

MOD

Your regex is very close. It current finds only words of exactly `count` length. To find words of `count` length or more, you need to add a comma to the notation: `{count,}`

```import re
def find_words(count, strang):
return re.findall(r'\w{'+ str(count) +',}', strang)  # <-- added comma before closing brace
```

Hi Chris, can you please explain the '+ str(count) +' of the code?

I had originally done this, which from the above answer, and attempt, proves to be incorrect.

```return re.findall(r'\w{count,}', string)
```

Chase, there are many solutions that work for this challenge. The key is creating the string with the correct syntax.

in the solution above, I corrected the posted problem which used string concatenation to build the regex string.

`str(count)` converts the value in `count` to a string. If `count` had a value of 3, `str(count)` would return the string "`3`". The string concatenation would then be:

```r'\w{'+ '3' +',}'

# which is the same as
r'\w{3,}'
```

You can use `count` directly in a formatted string using one of the following methods

```# simple substitution
r'\w{%s,}' % count

# format method. Use '{{' and '}}' to escape braces
r'\w{{{},}}'.format(count)

# format method with named fields. Use '{{' and '}}' to escape braces
r'\w{{{value},}}'.format(value=count)
```