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Aldo Rivadeneira
3,241 Pointsword_length.py: Still Getting Bummer
Im getting this :
Didn't get the right output. Output was [['123456'], ['Treehouse'], ['student'], ['Kenneth'], ['Python'], ['g0tcha']]. Length was 6.
When i test the code into my IDE it works or it seems to be work for me.
I'll try from to many ways but i don't know what's wrong :S
import re
# EXAMPLE:
# >>> find_words(4, "dog, cat, baby, balloon, me")
# ['baby', 'balloon']
def find_words(count, data):
# first i need to split the args
# then i need to store in to the list
# and make a loop to apply the regex, if it matches stores in a new list
# done
item_list = []
item_list = data.split(", ")
times = count * "\w"
regex = times + "+"
print(regex)
return_list = []
# print(times)
for item in item_list:
if re.findall(regex, item):
# print(re.match(r'\w\w\w\w+', item))
# print(times + "+" + item)
print(re.findall(regex, item))
return_list.append(re.findall(regex, item))
return return_list
# find_words(4, "dog, cat, baby, balloon, me")
3 Answers
Craig Dennis
Treehouse TeacherDo you want to append to the list or extend it?
Let me know if that hint doesn't do the trick ;)
Theresa Lee
8,072 PointsHey Aldo,
My initial solution was similar to yours and it also didn't work (via the challenge and via my idle). Eventually I discovered that the output of variable regex was not what I expected:
regex = "\w" + "{" + str(4) + ",}"
>>> regex
'\\w{4,}'
This meant that when we're using it in re.findall() it actually looks like this:
re.findall('\\w{4,}', item)
The answering post in https://teamtreehouse.com/community/wordlength shows a solution to this challenge, which I found helpful.
Aldo Rivadeneira
3,241 PointsOh i see, hum, so is i the regex pattern format the problem , well i need to study this, because this was make me nutts :P
Thank you !!
Kirsten Smith
3,484 PointsI think you are over complicating this challenge. Once you have split the string into a list of strings (which you did), all you need to do is check the length of each string and add it to a new list if length is greater than the count.
Aldo Rivadeneira
3,241 Pointsok i understand what you mean, ill try the following but im still getting the same error of the length, well in fact im doing the regex not counting the legth of the word.
The strange thing is in my IDE this works...
BTW, Thanks for your time!
import re
# EXAMPLE:
# >>> find_words(4, "dog, cat, baby, balloon, me")
# ['baby', 'balloon']
def find_words(count, data):
# first i need to split the args
# then i need to store in to the list
# and make a loop to apply the regex, if it matches stores in a new list
# done
item_list = []
item_list = data.split(", ")
regex = "\w" + "{" + str(count) + ",}"
return_list = []
for item in item_list:
if re.findall(regex, item):
print(item)
# print(re.findall(regex, item))
return_list.append(re.findall(regex, item))
return return_list
find_words(4, "dog, cat, baby, balloon, me")
Aldo Rivadeneira
3,241 PointsAldo Rivadeneira
3,241 Pointsoh i see!! , the append it's only for objects and extend is for the list.
Thanks a lot! Craig Dennis i was a little stuck with this.