Working with Logical Operators

Hi Miguel,

• Since the for loop (which is used to cycle through numbers 1 to 100, one by one) is already written for us, we get to write the if statement.

• This if statement will logically test for every number covered by the for loop (1 to 100) if the number is both an odd number and a multiple of 7.

• An even number never has a remainder when divided by 2. Therefore, we can deduce that if a number has a remainder after being divided by 2, it is an odd number. To evaluate for remainders, we use modulus division, using the % symbol.

• If a number is a multiple of 7, then it should divide by 7 evenly, with no remainder.

• That covers our if statement. After that, the challenge asks us to append the number to the results array if it passes our if statement. As stated in the for loop, we're referring to each of those numbers from 1 to 100 as 'n'. Thus, if a number passes the if conditions, then n gets added to the results array.

var results: [Int] = []

for n in 1...100 {
    // Enter your code below
    if n % 2 != 0 && n % 7 == 0 {
      results.append(n)
    }
    else {
    }
    // End code 
}

Hope this helps!

The code challenges are not made to be help us learn. They frustrate us so we look up the answer elsewhere. Dial down the difficulty for people who are just learning to code.

"An even number never has a remainder when divided by 2. Therefore, we can deduce that if a number has a remainder after being divided by 2, it is an odd number. To evaluate for remainders, we use modulus division, using the % symbol."

What if the number was 0? Would this then show up as odd number since 2 cannot go into it?