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iOS Swift Basics (retired) Control Flow Exercise: FizzBuzz Generator

Will Feldman
Will Feldman
3,121 Points
Posted by Will Feldman
Will Feldman
3,121 Points

Would the following code also work?

var number = 3

if number % 5 == 0 && number % 3 == 0 {
    println("FizzBuzz")
}
else if number % 3 == 0 {
    println("Fizz")
}
else if number % 5 == 0 {
    println("Buzz")
}

And as you change the var "number" it would print the correct result.

Jenna McCarter
Jenna McCarter
4,391 Points

That looks pretty good to me.

3 Answers

Franciscus Agnew
Franciscus Agnew
23,912 Points
Franciscus Agnew
Franciscus Agnew
23,912 Points

Hello Will,

The short answer... the code would work, but it may not work the way you intended!

The short solution...

var number = 3

if number % 5 == 0 && number % 3 == 0 {
    println("FizzBuzz")
}
else if number % 5 == 0 {
    println("Fizz")
}
else if number % 3 == 0 {
    println("Buzz")
}
else {
    do something... 
}

Good Luck,

Franciscus

Lukas Muller
Lukas Muller
7,347 Points
Lukas Muller
Lukas Muller
7,347 Points

Got the same result. Awesome!

John Scully
John Scully
1,018 Points
John Scully
John Scully
1,018 Points

Your code is identical to where I started and will definitely work if you pass it each individual value. But the real power of code is in the ability to automate so that the computer does all the work for you.

Simply replace your var with "for numbers in 1...50 {"

and you've got it. Just have to close the curly braces at the end of your code.