Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Dates and Times in Python Let's Build a Timed Quiz App Simple Time Machine

Write a function named delorean that takes an integer. Return a datetime that is that many hours ahead from starter.

my output is getting this: Bummer: delorean didn't return the right datetime. Got 2015-10-21 05:29:00.

can't see where I'm getting this wrong everything is changing except the hours :(

Thanks in advanced

time_machine.py
import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

def delorean(ahead):
    return starter.replace(hour=ahead)

2 Answers

Steven Parker
Steven Parker
221,329 Points

You're close, but instead of simply replacing the hour with the argument, you need to add the argument to the current hour:

    return starter.replace(hour=starter.hour+ahead)

Thanks very much Steven Parker it worked, I see the different in code length but not in practicality to me it reads the same. would you be able to explain the difference??

Thanks in advance

no worries I misread your comment thanks appreciate the help

can we not use a timedelta?

Michael Ford
Michael Ford
3,432 Points

Here is my solution using timedelta:

def delorean(value): return starter + datetime.timedelta(hours=value)

starter = datetime.datetime(2015, 10, 21, 16, 29)