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Python Dates and Times in Python (2014) Let's Build a Timed Quiz App Simple Time Machine

Posted by Kirome Thompson
Kirome Thompson
5,350 Points

Write a function named delorean that takes an integer. Return a datetime that is that many hours ahead from starter.

my output is getting this: Bummer: delorean didn't return the right datetime. Got 2015-10-21 05:29:00.

can't see where I'm getting this wrong everything is changing except the hours :(

Thanks in advanced

time_machine.py 
import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

def delorean(ahead):
    return starter.replace(hour=ahead)

2 Answers

Steven Parker
Steven Parker
229,644 Points
Steven Parker
Steven Parker
229,644 Points

You're close, but instead of simply replacing the hour with the argument, you need to add the argument to the current hour:

    return starter.replace(hour=starter.hour+ahead)
Kirome Thompson
Kirome Thompson
5,350 Points

Thanks very much Steven Parker it worked, I see the different in code length but not in practicality to me it reads the same. would you be able to explain the difference??

Thanks in advance

Kirome Thompson
Kirome Thompson
5,350 Points

no worries I misread your comment thanks appreciate the help

Adrian Torrente Tenreiro
Adrian Torrente Tenreiro
12,540 Points

can we not use a timedelta?

Michael Ford
Michael Ford
3,432 Points
Michael Ford
Michael Ford
3,432 Points

Here is my solution using timedelta:

def delorean(value): return starter + datetime.timedelta(hours=value)

starter = datetime.datetime(2015, 10, 21, 16, 29)