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Charles Harpke
33,986 PointsWrite a function named minutes that takes two datetimes and returns the number of minutes, rounded, between them.
Stuck as to how to round the minutes...Here is my code:
import datetime
datetime1 = datetime.datetime.now()
datetime2 = datetime.datetime.now()
def minutes(datetime1, datetime2):
return datetime1 - datetime2
import datetime
datetime1 = datetime.datetime.now()
datetime2 = now.timestamp()
def minutes(datetime1, datetime2):
return datetime1 - datetime2
Kenneth Love
Treehouse Guest TeacherPretty similar to what we did in one of the videos, actually.
>>> dt1 = datetime.datetime(2014, 12, 6, 9)
>>> dt2 = datetime.datetime(2014, 12, 6, 10, 30)
So dt1 is a datetime pointing to today at 9am. dt2 is the same but pointing at 10:30am instead.
>>> td = dt2 - dt1
Since dt1 is older than dt2, if I want the difference between them, I need to subtract dt1 from dt2. Just like I'd get the difference between 2 and 10 by doing 10 - 2 instead of 2 - 10.
If I look at td, I get:
>>> td
datetime.timedelta(0, 5400)
That's a timedelta, or difference between two times, that is 0 days and 5400 seconds.
OK, how do I convert seconds to minutes? Well, how many seconds are in a minute? 60! So I'd divide my seconds by 60 to get the number of minutes.
>>> td.seconds / 60
90.0
But the challenge wants a whole number, or integer, for the answer, so we have to use round(). I'm sure you can do the rest of this.
7 Answers
Kenneth Love
Treehouse Guest Teachertimedelta objects have a few almost-always-present attributes, like we go over in the video. They have days, seconds, and microseconds (there are a couple of others possible but pretty uncommon). So, you have a timedelta and it'll have seconds, so how would you use that to find minutes?
Wolverine .py
2,513 Pointsimport datetime
time_1 = datetime.datetime.now()
time_2 = datetime.datetime.now().replace(minute=59)
def minutes(time_1, time_2):
delta = time_2 - time_1
delta_seconds = delta.total_seconds()
return round(delta_seconds/60)
this worked for me:)
Don Han
7,811 PointsHere's my answer that went through.
import datetime
def minutes(old, new): diff = new - old return round(diff.total_seconds() / 60)
Charles Harpke
33,986 PointsGot it...thank you.
Christos Peramatzis
16,428 Pointsi can't understand why this isn't working
def minutes(date1, date2):
sec1 = date1.total_seconds()
sec2 = date2.total_seconds()
mins = (sec2 - sec1) / 60
return round(mins)
sorry for all the spaces but I could not format it differently
Kenneth Love
Treehouse Guest Teacherdatetimes don't have total_seconds, only timedeltas do. The function receives two datetime objects. So to get from a datetime to a timedelta, what do you need to do?
Christos Peramatzis
16,428 Pointssubtract them..
Trust Mujaka
1,821 Pointsimport datetime def minutes(datetime1, datetime2): return round((datetime2-datetime1).total_seconds()/60)
Charles Harpke
33,986 PointsCharles Harpke
33,986 Pointssorry....still not quite seeing it...