Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
Write a function named time_machine that takes an integer and a string of "minutes", "hours", "days", or "years". This d
Is that OK to write datetime.timedelta(string = integer)?
import datetime starter = datetime.datetime(2015, 10, 21, 16, 29) # Remember, you can't set "years" on a timedelta! # Consider a year to be 365 days. ## Example # time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34) def time_machine(integer, string): if string == "years": duration = datetime.timedelta(days = integer* 365) else: duration = datetime.timedelta(string = integer) return starter + duration
Chris FreemanTreehouse Moderator 68,082 Points
The left-side of a keyword argument is not interpreted which causes the error
string is not a valid keyword argument. If it were interpreted, then
days, in the previous statement, would also need defining.
There are two ways to use a variable as a keyword argument:
- use an
if/elif/elsestatement to have a unique
durationassignment for each timedelta argument type
- create a dict with the key
integer, then use
**to expand this dict in the argument list
Post back if you need more help. Good luck!!!
Anupam Kumar3,795 Points
What could be wrong with this Code
import datetime starter = datetime.datetime(2015, 10, 21, 16, 29) # Remember, you can't set "years" on a timedelta! # Consider a year to be 365 days. ## Example # time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34) def time_machine(strin,integer): return starter+datetime.timedelta(strin=integer) time_machine("minutes",5)
thanks in advance
[MOD: added ```python formatting -cf]