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# Write a function named time_machine that takes an integer and a string of "minutes", "hours", "days", or "years". This d

Hey there, Struggling with datetimes in general. It Will def be a subject I come back to again. Can't figure out how to calculate "years"... please help.

Thanks, Matt

time_machine.py
```import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(take_int, take_string):
if take_string == 'minutes':
offset = datetime.timedelta(minutes=take_int)
elif take_string == 'hours':
offset = datetime.timedelta(hours=take_int)
elif take_string == 'days':
offset = datetime.timedelta(days=take_int)
else:
offset = datetime.timedelta(days,365=take_int)
return starter + offset
```

MOD

Try passing in a little calculation to the else block. All you need to do is multiply the `timedelta` day by the integer 365

Jonathan Grieve would that be before the "offset = datetime.timedelta(days,365=take_int) part... sadly I'm still not getting it

I'll give you a little bit more of a nudge. :)

```else:
offset = datetime.timedelta(days=take_int*365)
```

It's just like what you did before in the last `else if` except in this block, if none of the other conditins match you're getting the day timedelta and simply multiplying that value by 365.

Jonathan Grieve thanks! I'm going to be watching and rewatching the DateTime videos... for some reason, it's a concept that isn't sticking. Has anyone else struggled with this set of videos by Kenneth Love?

Here's my response:

def time_machine(take_int, take_string): if take_string == 'minutes': offset = datetime.timedelta(minutes=take_int) elif take_string == 'hours': offset = datetime.timedelta(hours=take_int) elif take_string == 'days': offset = datetime.timedelta(days=take_int) else: offset = datetime.timedelta(days=take_int*365) return starter + offset