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Python Python Basics (2015) Letter Game App Even or Odd Loop

"Wrong number of prints"?

OK as this point I'm not sure what may be wrong. Any takers?

even.py
import random
start=5

def even_odd(num):
    num= random.randint(1, 99) 
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2


while start is True:
    if even_odd(num) == False:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start-=1    

1 Answer

Jon Wood
Jon Wood
9,884 Points

This is just a guess when looking at the code, but in the while loop you check if start is True. However you have it initialized as an int and take one away within the loop. It doesn't look like the loop would ever end.

Once it decrements down to "0" wouldn't it end because "0" is false?