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Python Python Basics (2015) Letter Game App Even or Odd Loop

"Wrong number of prints?" -- I don't know what the error references, I don't know where to alter my code.

I've been stuck on this for a while now. I have no idea what the "Bummer" message is referring to so I am lost in finding a solution.

I have moved the while loop all over the program and can't seem to shake this error. Any help?

even.py
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

def game():
  while start:
    random.randint(1, 99)
    if even_odd(num) == True:
      print("{} is true".format(num))
  else:
    print("{} is odd".format(num))
  start -= 1

1 Answer

Andrew,

You're close, but there are a few key problems. The game() function is not necessary, and the conditional for even_odd(num) is simply if even_odd(num):. Also, you forgot to assign the randomized number to the variable num.

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    num = random.randint(1,99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1