Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Logic in Python Try and Except

You're doing great! Just one more task but it's a bigger one. Right now, we turn everything into a float.

You're doing great! Just one more task but it's a bigger one.

Right now, we turn everything into a float. That's great so long as we're getting numbers or numbers as a string. We should handle cases where we get a non-number, though.

Add a try block before where you turn your arguments into floats.

Then add an except to catch the possible ValueError. Inside the except block, return None.

If you're following the structure from the videos, add an else: for your final return of the added floats

trial.py
def add(n1, n2)
    try:
        a = float(n1)
        b = float(n2)
    except ValueError:
        return None
    else:
        return True

1 Answer

andren
andren
28,558 Points

There are two issues:

  1. You are missing a colon : after your function declaration
  2. In the else block you are meant to return the result of adding the two numbers together, you are just returning the Boolean True.

If you add the colon and add the two numbers together like this:

def add(n1, n2): # <- Added :
    try:
        a = float(n1)
        b = float(n2)
    except ValueError:
        return None
    else:
        return a + b # Return two numbers added together

Then your code will pass.