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reza sajadian
718 PointsZippy combo function doesn't work. Help me please.
I don't have a clear idea how shall my code work on this exercise.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo():
for item in enumerate(a):
for item in enumerate(b):
target = '{}: {},{}'.format(index, a, b)
return target
2 Answers
Chris Freeman
Treehouse Moderator 68,423 PointsYou are on the right path. The end goal is a list of tuples. Also enumerate generates two items each iteration: an index and a member of the container. So the for loop must have two variables to receive them. You can use the index of the first loop to generate the second tuple item. The function needs two parameters for the two iterables passed in.
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(a, b):
# initialize target
target = []
for index, item in enumerate(a):
# append tuple to target
target.append((item, b[index]))
return target
Mike Tribe
3,827 Pointsdef combo(itr1, itr2):
tuplist = []
index = 0
for item in itr1:
tuplist.append((item, itr2[index]))
index += 1
return tuplist