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PHP Build a Simple PHP Application Creating the Menu and Footer Variables and Conditionals

Simon Strömberg
Simon Strömberg
1,423 Points
Posted by Simon Strömberg
Simon Strömberg
1,423 Points

Change the value in the flavor variable to cookie dough. Preview the code and make sure the message appears.

How do i solve task nr 4? HELP thanks

index.php 
<?php

$flavor = "vanilla"; 
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
?>

<?php 
if ($flavor = "cookie dough"){
 echo "<p>Randy's favorite flavor is " . $flavor .  " also! </p>";
}
?>

2 Answers

Rich Bagley
Rich Bagley
25,869 Points
Rich Bagley
Rich Bagley
25,869 Points

Hi Simon,

This post should hopefully help.

-Rich

Simon Woodard
Simon Woodard
6,545 Points
Simon Woodard
Simon Woodard
6,545 Points

Hi Mate,

You need to set the variable $flavor to 'cookie dough' before the if statement. You can do this by using the single equals sign.

In the if statement you need to run the test to see if $flavor now equals cookie dough, to run this test you need to use the double equals sign.

Your code should look something like this.

<?php

$flavor = "vanilla"; echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; ?>

<?php $flavor = "cookie dough"; if ($flavor == "cookie dough"){ echo "<p>Randy's favorite flavor is " . $flavor . " also! </p>"; } ?>