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JavaScript JavaScript Foundations Functions Return Values

Checking if 'Undefined'

Around line 17, create a function named 'arrayCounter' that takes in a parameter which is an array. The function must return the length of an array passed in or 0 if a 'string', 'number' or 'undefined' value is passed in.

var my_arrray = [ 1 , 2 , 3 ];
      function arrayCounter(my_array){
        if (my_array.isArray) {
            var a = my_array.length
          } 
        else {
        a = 0
          }
        return a
      }

Bummer! You're not checking if 'undefined' is being passed in

Please help

5 Answers

Carla Thomas
seal-mask
.a{fill-rule:evenodd;}techdegree
Carla Thomas
Front End Web Development Techdegree Student 16,039 Points

I found the "answer" here in the forum...it makes sense but I cannot get it to work in the challenge. Here's the link to the answer....please let me know if you can make that code work

https://teamtreehouse.com/forum/this-is-driving-me-crazy-what-am-i-missing

The answer

function arrayCounter(array) 
      { if (typeof array === "string" || typeof array === "number"|| typeof array === "undefined")
      { return 0; } 
      else { return array.length; } }

Programmatically this code works. Why it doesn't work in the challenge I couldn't say as I haven't taken the javascript track yet

if(typeof my_array === 'undefined'){
   // handle error
 }
else
{
// your code here etc...
}

...

Carla Thomas i got it right the first time as well but now when i try it, it keeps on giving me syntax error...strange

Adama Sy
Adama Sy
7,076 Points

function arrayCounter (array) { if (typeof array === "string"){ return 0; } if (typeof array === "undefined"){ return 0; } if (typeof array === "number"){ return 0; }

    else {return array.length};
     }