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David Wright
4,437 Pointscounts.py
code shows my two attempts, both failed.
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members(my_dict, my_list):
count = []
for item in my_list and my_dict:
count += 1
return count
def members(my_dict, my_list):
count = []
for item in my_list:
if item in my_dict:
count += 1
return count
1 Answer
Josh Keenan
19,652 PointsTake a look at this thread, Chris explains how to tackle the challenge really well!
https://teamtreehouse.com/community/how-do-i-create-the-right-members-function