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Shawndee Boyd
6,002 PointsCreate a function named search_challenges that takes two arguments, name and language.
I may be reading this wrong or over-thinking it but any help would be appreciated.
from models import Challenge
def create_challenge(name, language, steps=1):
Challenge.create(name=name,
language=language,
steps=steps)
def search_challenges(name, language):
count = 0
if name == name | language == language:
return Challenge
5 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsFollowing the form used in the video, select all the Challenges then filter using where().
Edit: added parens around each condition
def search_challenges(name, language):
"""Search challenge by name and language."""
# select all the challenges
challenges = Challenge.select()
# filter by name and by language
challenges = challenges.where((Challenge.name==name) | (Challenge.language==language))
# return filtered challenges result
return challenges
Also, according to this thread, Kenneth Love, provides an alternative answer that combines both statements and uses a "comma" notation:
Challenge.select().where(
Challenge.name.contains(name),
Challenge.language==language
)
Ary de Oliveira
28,298 Pointsfrom models import Challenge
def create_challenge(name, language, steps=1): Challenge.create(name=name, language=language, steps=steps) def search_challenges(name, language): """Search challenge by name and language."""
challenges = Challenge.select()
challenges = challenges.where((Challenge.name==name) | (Challenge.language==language))
return challenges
Shawndee Boyd
6,002 PointsThe code you have provided is saying "Didn't find the right number of records".
Chris Freeman
Treehouse Moderator 68,441 PointsRight you are! Sorry, pasted wrong version. I've updated the answer by adding parens around each condition.
Shawndee Boyd
6,002 PointsI should have seen that!! Thank you!!!
wads wdsf
Python Web Development Techdegree Student 1,678 Pointsdef search_challenges(name,language):
return Challenge.select().where(Challenge.name==name and Challenge.language==language)
Colby Work
20,422 PointsColby Work
20,422 PointsI got stuck on this. The way the challenge is worded threw me off ("You don't need boolean and or binary & for this, just put both conditions in your where()"). I must have missed the part in the video where "|" is mentioned. Thanks for this.