Disemvowel Challenge

You're on the right track, you just need some tweaking!

Let's start with your list. Turning word into list(word) is great, except right now, you're generating a new list from scratch in your return statement. If you store the list in a variable within the function, before the loop, your loop has access to it, and it will update each time through your loop.

def disemvowel(word):
    word_list = list(word)
    for letter in word_list:
        # do something
    return word_list

Next, you need to check for both upper and lowercase vowels. The easiest way to do this is to ask if letter.lower() is in the list.

if letter.lower() in ['a', 'e', 'i', 'o', 'u']:
    # do something

That way, if the letter in word is uppercase, your loop will convert it to lowercase before checking it against your vowel list.

Now to the loop. The loop isn't going to iterate over each letter in word_list as much as it will iterate over each index number in word_list. This means that each time you remove a letter, every following letter's index number will change by 1, causing the letter right after a vowel to be skipped. If there are two vowels in a row, the second one will never get checked. There's a couple ways around this, but one is to create a new list and append non-vowels to it, rather than removing vowels from the old list. You can do this by checking to see if a letter is not in your vowels list.

new_list = []    # store an empty list in a variable
for letter in word_list:
    if letter.lower() not in ['a', 'e', 'i', 'o', 'u']:
        new_list.append(letter)

Finally, you're currently returning the list itself, but you need to turn the list back into a string before returning it. You can use .join() to accomplish this. Let me know how it goes!