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iOS Swift Basics (retired) Control Flow Exercise: FizzBuzz Generator

Posted by wwyattw
wwyattw
10,389 Points

How to check a number only?

Could anyone help me with this? I wanted to create something that you can check a number instead of numbers in a range.

var number = 80

for aNumber in number { if (aNumber % 3 == 0) { print("Fizz") } else if (aNumber % 5 == 0) { print("Buzz") } else if (aNumber % 3 == 0) && (aNumber % 5 == 0) { print("FizzBuzz") } else { print("nill") } }

1 Answer

Paul Brazell
Paul Brazell
14,371 Points
Paul Brazell
Paul Brazell
14,371 Points

Not sure if I entirely understand your question. Do you mean that you want to check just one number for the condition? If that is the case, then you would just not do a for in loop. Just do the if statement on the number. 

var aNumber = 80

if (aNumber % 3 == 0) { 
     print("Fizz") 
} 
else if (aNumber % 5 == 0) {
     print("Buzz") 
}
 else if (aNumber % 3 == 0) && (aNumber % 5 == 0) { 
     print("FizzBuzz")
 } 
else {
     print("nill") 
}

Provide more details if that doesn't answer your question.

lynnnicole
lynnnicole
590 Points

It seems like that's what is being asked.

Also Ge Wang, will want to move the code around for logic:

var aNumber = 80
if (aNumber % 3 == 0) && (aNumber % 5 == 0) { 
     print("FizzBuzz")
}
else if (aNumber % 3 == 0) { 
     print("Fizz") 
} 
else if (aNumber % 5 == 0) {
     print("Buzz") 
}
else {
     print("nill") 
}