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Minh Mai
2,649 PointsInstance Methods Challenge
The output keeps saying "Bummer! Try Again!" so I can't really figure out where my code goes wrong.
I'm supposed to create a score method that'll increase the current score by 1 depending on the selection. I'm not sure what is wrong with my code. Thanks!
class Game:
def __init__(self):
self.current_score = [0, 0]
def score(self):
score_choice = input('[1] or [2]').astype(int)
if score_choice == 1:
self.current_score[0] = 1
else:
self.current_score[1] = 1
1 Answer
William Li
Courses Plus Student 26,868 PointsAdd a score method to Game that takes a player argument that'll be either 1 or 2.
The challenges states that you need to pass in the required argument player to the score method, but your method doesn't have it. And there're other issues as well.
-
score_choice = input('[1] or [2]').astype(int)you do not need this line, because we aren't asking user for input here. -
if score_choice == 1:the condition should be checking against theplayerargument. -
self.current_score[0] = 1, you need to increment the first item of self.current_score by 1, NOT assign 1 to it; same goes true forself.current_score[1] = 1
class Game:
def __init__(self):
self.current_score = [0, 0]
def score(self, player):
if player == 1:
self.current_score[0] += 1 # increase the 1st item in the self.current_score list by 1
if player == 2:
self.current_score[1] += 1 # increase the 2nd item in the self.current_score list by 1
Hope it helps.
Jason Anello
Courses Plus Student 94,610 PointsThe score method could also be a 1-liner since the index to be incremented is always 1 less than the player number. You can simply increment the index that is player - 1
def score(self, player):
self.current_score[player - 1] += 1
Tony McCabe
4,889 PointsThis is the answer which passes the challenge thanks
Jason Anello
Courses Plus Student 94,610 PointsJason Anello
Courses Plus Student 94,610 PointsKenneth Love
This code challenge is passing with the correct code but it's also passing with code that always sets the score to 1.