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iOS Objective-C Basics (Retired) Foundation Framework NSArray

NSArray challenge

NSArray *drinks = [ @"juice", @"water", @"coffee" ]; for (NSString *string in drinks) { NSLog(@"%@", string); }

What am I doing wrong? specially on the "for in" loop

2 Answers

Mike Baxter
Mike Baxter
4,442 Points

First, try to output the count of your array to see if it actually has 3 items.

NSLog(@"%d", [drinks count]);

It'll probably return 0. It looks like you may have missed the @ before the NSArray literal. Should look like this:

NSArray *drinks = @[ @"juice", @"water", @"coffee" ];

for (NSString *string in drinks) {
    NSLog(@"%@", string);

Looks almost the exact same, but the crucial code in making an array with literals is

@[obj 1, obj 2, obj 3]

Thank you