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Christian Mangeng15,969 Points
Question to Python regular expressions (find_emails challenge)
I have a special question to this challenge. I'm not interested in the actual solution of the challenge, as I've already solved it using:
def find_emails(my_string): return re.findall(r'[-\w\d+.]+@[-\w\d.]+', my_string)
But what confused me about it at the beginning was the example output given (see below), in which the ".love" and "+case" are missing in the first and third address. Now my question is: Is there a way to output the emails EXACTLY like in the example given, using regular expressions? It would mean to ignore the . and + characters of the first part of the email, as well as the following letters before the @.
import re # Example: # >>> find_email("firstname.lastname@example.org, @support, email@example.com, firstname.lastname@example.org") # ['email@example.com', 'firstname.lastname@example.org', 'email@example.com']
Chris FreemanTreehouse Moderator 67,763 Points
If I'm understanding your question correctly, there is not a way to directly get the exact example output show in the challenge.
# Example: # >>> find_email("firstname.lastname@example.org, @support, email@example.com, firstname.lastname@example.org") # ['email@example.com', 'firstname.lastname@example.org', 'email@example.com']
The regex acts like a filter that either matches or doesn't. If it matches it outputs the match, otherwise no output. To drop the ".love" from the email, that is, everything between the last period of an address and the at-sign, the regex would need to define a group for each desired section then reassemble the parts to form a whole address.
Your question has me wondering if the example code and results are out of date in the challenge and may need updating. Tagging Kenneth Love to review the example code in the challenge for correctness.