Regular Python Expressions - Challenge task 2 of 2. Please clarify the question for me.

I'm a native English speaker and this forum thread was just confusing..

Malcolm Jury was almost correct in the line of code he posted.

return re.search(r'\d' * number, string)

However, taking into account the original poster's def:

def numbers(count, user_string):

I think Malcolm's line of code would have to be adjusted (re-factored) to fit the rest of the code as follows:

import re


def first_number(strings):
  data = re.search(r'\d', strings)
  return data

def numbers(count, user_string):
  return re.search(r'\d' * count, user_string)

Hey Thanks for the explanation Kenneth Love. That was actually rather easy. The phrasing of the question just threw me off, as I wasn't able to figure out what I was expected to do. It probably didn't help that I was doing the lesson at midnight after a full day's work. :)

Malcolm Jury

I'm not sure if you figured it out yet, but you basically just have to multiply the regular expression number operator by the number variable and search for it in the string. Something like this:

return re.search(r'\d' * number, string)

Where number and string are your input variables of course.

Cheers!

You're going to get a count and a string. In that string, find where there are count numbers in a row in the string. So if count is 5, find 5 numbers in a row. If it's 3, find 3 numbers in a row.

Yes . i did it . Again a Bummer !!!!....

def numbers(count, str): return re.match(r'\d' * count,str)

Got it . But i think little rephrase in question needed ...Thank you for your quick response.

I understand that if the count was 5 then something like this would produce the result

return re.search(r'\d\d\d\d\d', aString)

Ive attempted to build up that r'/d/d/d/d/d' string using concatenation but am getting no where, it keeps on outputting none when i run the script

Hi can anyone tell me is this the right solution ?.

return re.search(r'\d' * number, string)

Task :

write a function named numbers() that takes two arguments: a count as an integer and a string. Return a match for exactly count numbers in the string. Remember, you can multiply strings and integers to create your pattern.

The complete Code:

import re

def first_number(str): return re.search(r'\d', str)

def numbers(count, str): return re.match(r'\w' * count, str)