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Alhagie Jobe
15,388 PointsThe for loop cycles over list items and applies a color to each item using the values stored in the colors array. For ex
The for loop cycles over list items and applies a color to each item using the values stored in the colors array. For example, the first color in the array ( #C2272D) is applied to the first list item, the second color (#F8931F) to the second list item, and so on. Complete the code by setting the variable listItems to refer to a collection. The collection should contain all list items in the <ul> element with the ID of rainbow.
var listItems = document.querySelectorAll("#rainbow");
var colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
<!DOCTYPE html>
<html>
<head>
<title>Rainbow!</title>
</head>
<body>
<ul id="rainbow">
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="js/app.js"></script>
</body>
</html>
2 Answers
Steven Parker
229,732 PointsThe instructions say "The collection should contain all list items in the <ul> element with the ID of rainbow."
The selector used in the code here is setting the variable to the "rainbow" ul itself instead of the li items within it.
Hint: this might be a good place for a descendant selector or a direct child selector.
Daven Hietala
8,040 PointsI was able to find the answer on this thread..
"dallas kelley on May 24, 2018 While document.getElementsByTagName('li'); works for this particular problem it wouldn't work if you had more than one list that had different IDs. For example document.getElementsByTagName('li'); would select all <li> tags in a list that may not need to be selected where as document.querySelectorAll("ul#rainbow > li"); will only select <li> tags inside the UL with the ID: rainbow."
Good luck!
Steven Parker
229,732 Points
Marcelo Pereira
12,169 PointsMarcelo Pereira
12,169 Pointsi already do that and still tell: There was an error with your code: TypeError: 'undefined' is not an object (evaluating 'listItems[i].style')
Steven Parker
229,732 PointsSteven Parker
229,732 PointsYour issue is probably earlier in the code. Try creating a new question where you can put your complete code and perhaps someone can help spot it.