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Python Python Collections (2016, retired 2019) Dictionaries Word Count

wordcount.py runs as expected on Workspaces, but doesn´t pass on the challenge

I tried several times... and after checking other posts I know my error is not the split("")...

What am I missing here??

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

count = 1
wordcount = {}

def word_count(x):
    word = x.lower().split() # hago lista. Cada palabra es un item en la lista
    for z in word:
        if z in wordcount.keys():
            wordcount[z] = count + 1
        else:
            wordcount[z] = count
    return wordcount

4 Answers

wordcount = {}

def word_count(x):
    word = x.lower() # hago lista. Cada palabra es un item en la lista
    for z in word.split():
        if z in wordcount.keys():
            wordcount[z] += 1
        else:
            wordcount[z] = 1
    return wordcount

this is your code

>>> x = "I do not like it Sam I Am"
>>> count = 1
>>> wordcount = {}
>>> def word_count(x):
...     word = x.lower().split()
...     for z in word:
...             if z in wordcount.keys():
...                     wordcount[z] = count + 1
...             else:
...                     wordcount[z] = count
...     return wordcount
...
>>> word_count(x)
{'do': 1, 'like': 1, 'sam': 1, 'i': 2, 'am': 1, 'it': 1, 'not': 1}
>>> x = "I do not like it Sam I Am am am sam sam sam"
>>> word_count(x)
{'do': 2, 'like': 2, 'sam': 2, 'i': 2, 'am': 2, 'it': 2, 'not': 2}

Thanks ASHOK. I checked your code and we solved things in a different order... but all steps are there.

I tried the other suggested string and the count of words was correct.

I still can see what I am doing wrong.

Ok... got it. It's working now. I saw my mistake.

Much appreciated ASHOK